## How many RAM chips of 256×8 are required to provide a RAM capacity of 2048 bytes for any system also mention size of decoder?

Hence the number of such RAM chips required, or 16 chips.

## How many chips are needed to provide a memory capacity of 1024 bytes?

1024 is , so you need 10 address lines, assuming each address addresses one byte (the usual case).

## How many 128×8 RAM chips are needed to provide a memory capacity of 4096×16?

Memory chips can hold memory either temporarily through random access memory or permanently through read only memory. The answer to the above question is 4096×16/128×8 o2r ^12×2^4/2^7×2^3 or 2^16/2^10 =2^6.

## How many 128k 16 RAM chips are needed to provide a memory capacity of 2 MB?

A) 16K bytes = 16 x 1024 x 8 => 128 chips.

## How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system?

8 chips
7. How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system? Explanation: One 1024 * 1 RAM chips is of 1-bit. SO, for construction of 1024 * 8 RAM chip of 8-bits, it will require 8 chips.

## How many chips are needed to provide a memory capacity of 16 K bytes if a computer uses RAM chips of 1kx8 capacity?

Explanation: RAM chip size = 1k ×8[1024 words of 8 bits each] RAM to construct =16k ×16 Number of chips required = (16k x 16)/ ( 1k x 8) = (16 x 2) [16 chips vertically with each having 2 chips horizontally] So to select one chip out of 16 vertical chips, we need 4 x 16 decoder.

## How many 512 * 8 RAM chips are needed to provide a memory capacity of 2048 bytes?

Since 8 bits = 1 byte, Each RAM chip has 64 x 1 byte = 64 bytes. Thus the number of chips to address a memory capacity of 2048 bytes will be, 2048/64 = 32 chips.

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## How many 1kb IC’s are required to build 1mb memory?

Answer: A total of 32 RAM chips are needed to build 1 MB of memory. = 32 chips. Thus, 32 RAM chips are needed to build 1 MB of memory.

## How many RAM chips are there per memory word?

The design calls for two chips per 16–bit word. One chip holds the high–order byte for the word. The other chip holds the low–order byte for the word. Suppose that a 2M x 16 main memory is built using 256K x 8 RAM chips and memory is word addressable.

## How many 128 16 RAM chips are needed to provide?

Answer: 16K bytes = 16 x 1024 x 8 => 128 chips.

## How many memory chips does 512 8 have?

Pictorial Description (Design of 512×8 RAM):

From the above calculations, we see that we need four 128 x 8 RAM chips to design a 512 x 8 RAM size. If only the number of words is increasing then all chips will be arranged vertically.

## How many 1024b memory chips are required for designing 8kb memory design?

We know that 1 byte = 8 bits and 1K = 1024bytes. Given, 16K bytes = 16 * 1024 * 8. = 8.

## How many different addresses are required by the memory that contains 16k words?

There are 1024 bytes in one k byte. A 16k ram would therefore need 1024*16 = 16384 addresses.

## How many address lines are used in 4k memory?

12 address lines are require for 4k memory.

## How many lines of the address bus must be used to access computer system memory how many of these lines will be common to all chips?

How many 128 × 8 RAM chips are needed to provide a memory capacity of 2048 bytes? How many lines of the address bus must be used to access 2048 byte of memory?

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## Which of the memory holds the information when the power supply is switched off?

Discussion Forum
Que.Which of the memory holds the information when the Power Supply is switched off?
b.Dynamic RAM
c.EEROM
d.None of the above

## How many address lines are needed for memory?

If n=2, you can address 2 locations (0, 1, 2, and 3). As you can see, number of addressable locations = n^2. This means that n=log(1024) to the base 2. Thus, n=10.

## How many address lines are necessary on the chip of 4k byte memory?

Detailed Solution. So, 12 bits are needed to address 4k memory locations.

## What is the number of address lines required for 1 MB memory?

“20” address lines or address bus are required to span “1MB” memory space.

124K
138K
1416K
1532K

## How is memory capacity calculated?

Instead, we use a set of standard sizes that scale up as memory requirements get larger: 1 bit = a single 1 or 0. 4 bits = a nibble.

Calculating Memory Size.
StorageTransfer
1 MegaByte = 1000 KiloBytes1 MebiByte = 1024 KibiBytes
1 GigaByte = 1000 MegaBytes1 GibiByte = 1024 MebiBytes
1 TeraByte = 1000 GigaBytes1 TebiByte = 1024 GibiBytes

## How many address and data lines will be there for a 16M 32 memory system Mcq?

How many address and data lines will be there for a 16M x 32 memory system? d. None of the above Correct solution is (c). Since there are 16M words, the number of address lines will be 24, since 224 = 16M.